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I will award you best answer if you can help!

The length of a rectangle is 9 more than its width. Write and solve an equation to find the width of the rectangle if its perimeter is 38 inches.

 
Anonymous

Asked by Anonymous at 11:21 AM on Mar. 28, 2013 in Just for Fun

This question is closed.
Answers (12)
  • I don't know if this is the right way to do it according to algebra, but what I came up with is:

    38-(2x() =
    38-18 =
    20

    4 times X equals 20

    x = 5

    (5+9)+(5+9)=5+5 = 38
    Ballad

    Answer by Ballad at 11:54 AM on Mar. 28, 2013

  • Ugh! Not worth BA, LOL
    PMSMom10

    Answer by PMSMom10 at 11:25 AM on Mar. 28, 2013

  • Do your own homework.
    Anonymous

    Answer by Anonymous at 11:33 AM on Mar. 28, 2013

  • balagan_imma

    Answer by balagan_imma at 11:45 AM on Mar. 28, 2013

  • eleventy billion
    PartyGalAnne

    Answer by PartyGalAnne at 2:27 PM on Mar. 28, 2013

  • 1
    LostSoul88

    Answer by LostSoul88 at 11:40 AM on Mar. 28, 2013

  • Purple
    3libras

    Answer by 3libras at 11:48 AM on Mar. 28, 2013

  • You never award BA. Ever
    Anonymous

    Answer by Anonymous at 12:46 PM on Mar. 28, 2013

  • 17-22-45...oh wait that was my locker number in school.
    ILovemyPaulie

    Answer by ILovemyPaulie at 1:34 PM on Mar. 28, 2013

  • X is the width; X+9 is the length. Perimieter is 2 widths plus 2 lengths. So 2X + 2(X+9) =38. 2X + 2X +18 = 38. 4X = 20. X=5. Going back and plugging it in you have width =5 and the length = 14. 5+5+14+14 = 38 for the perimeter. Please double check my work!!
    silverthreads

    Answer by silverthreads at 3:01 PM on Mar. 28, 2013

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