Honestly please help me, im not a kid looking 4 answers this is just a part of a huge geomery booklet im trying to finish so that i can get my highschool diploma. I need to finish this asap because i have an interview coming up and i need my diploma. im a young mom of an 8 month old baby boy. in real need of that job. PLEASE HELP ME WITH THESE.
1) The height of a triangle is four times the length of the base. Find the base and height of the triangle if the area is 18 square inches.
2)The length of a rectangle is 5 meters longer than the width. Find the length and width if the perimeter is 54 meters.
3)Find the area of a trapezoid which has a measure of 7 meters for its height and 4 meters and 6 meters for its two bases.
4)Find the area of a parallelogram with height 6 inches and base 11 inches.
5)Find the perimeter and area of a square with a 12 ft. side.
6)Find the area of a triangle with a base 13 ft. and
Asked by Anonymous at 6:23 PM on Sep. 16, 2009 in Just for Fun
Answer by Anonymous at 6:26 PM on Sep. 16, 2009
Answer by Anonymous at 6:46 PM on Sep. 16, 2009
Answer by jesse123456 at 7:03 PM on Sep. 16, 2009
Answer by mama4Christ361 at 7:05 PM on Sep. 16, 2009
I think the formula you gave for number 5 is for a triangle. A=1/2bh. Her problem was for a square with one side of 12 ft. So, perimeter is s+s+s+s or 4(12)=48 ft. The area is area=length times width or 12 times 12 = 144 ft^2. The area formula for your number 5 can be used to answer number 1. Plug in the values and work for the unknown. This is basic 7th grade math (which I teach).
Answer by jesse123456 at 7:27 PM on Sep. 16, 2009
Answer by mama4Christ361 at 7:49 PM on Sep. 16, 2009
This might be 7th grade math for the students of today. I took this math in college in a course called "elementary and intermediate algebra," and presently as an apprentice in sheetmetal. I worked these out with my son, who is in college now studying to be an engineer. I kept my worksheets, in case you wanted to contact me direcly. I couldn't solve for problem #6 because the info was incomplete. It does no good to know the answer, if you don't know how you arrived at it.
(1) b=3, h=12, formula (1/2 X b) X H=area, (2) L=16, w=11, p=54, formula 2b + 2h=perimeter, (3) h=7, a=4, b=6, area =35 sq", formula a=h/2 X (a+b), (4) h=6, b=11, area =66, formula hxb=area, (5) p=48ft, a=144sq. ft, formulas permeter = 4s, area =(bxh)sq
Answer by Ewadun at 2:05 AM on Sep. 17, 2009
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