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Geometry question

An isoseceles triangle has two sides of equal length. The length of the third side is 3 ft less than twice the length of an equal side.

Find the length of the equal sides when the perimeter is 41 ft.

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Please let me know how you got your answer.

 
Anonymous

Asked by Anonymous at 8:29 PM on Feb. 28, 2011 in

This question is closed.
Answers (3)
  • The sides are 11, 11, and 19.

    You need to add it up like this. You said the third side is 3 feet less than twices the length of an equal side. If the equal side is x than that means the third side is 2x-3. Then your formula is (2x-3) +x+x=41. Then you can solve the formula. You will have 4x+3+41. You then need to subtract the three from both sides making it 4x=44. You then divide both sides by the 4 making it that x=11. Then you plug the 11 into the formula for the third side 2*11 equals 22. 22-3=19.
    layh41407

    Answer by layh41407 at 8:39 PM on Feb. 28, 2011

  • That should say that 4x+3=41
    layh41407

    Answer by layh41407 at 8:42 PM on Feb. 28, 2011

  • Draw a picture. Label the sides with the algebraic formulas. A=B. A+B+C=41
    rkoloms

    Answer by rkoloms at 8:36 PM on Feb. 28, 2011

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