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2 Bumps

Any math experts?

Wondering if anyone on here could solve this?

Janet invested $26,000 part at 6% and part at 3%. If the total interest at the end of the year is $1080, how much did she invest at 6%?

Answer Question
 
Anonymous

Asked by Anonymous at 10:31 PM on Mar. 6, 2011 in Just for Fun

Answers (10)
  • ouch my head hurts, Janet should have gone on a spending spree instead
    myheartx4

    Answer by myheartx4 at 10:34 PM on Mar. 6, 2011

  • LOL do your own math homework. This is not just for fun.
    parajumper3

    Answer by parajumper3 at 10:36 PM on Mar. 6, 2011

  • 0.06 x m + 0.03 x (26000 - m) = 10 800. Solve for m. (m is the about invested at 6%)
    judimary

    Answer by judimary at 10:43 PM on Mar. 6, 2011

  • Assuming they are straight interest, no componding. $16000 at 3% and $10,000 at 6%. The formula you are solving for is (26000-X) * 6% + X*3% = 1080. You solve for X.
    Olivia4116

    Answer by Olivia4116 at 10:47 PM on Mar. 6, 2011

  • HUH ???
    myheartx4

    Answer by myheartx4 at 10:54 PM on Mar. 6, 2011

  • In other words, she invested $1 080 at 6% pa. (assuming simple interest).
    judimary

    Answer by judimary at 11:18 PM on Mar. 6, 2011

  • You're wrong, Olivia4116, that is the equation for finding how much was invested at 3%.
    judimary

    Answer by judimary at 11:20 PM on Mar. 6, 2011

  • Sorry, my final answer above is wrong. You solve .06 x m + 0.03(26000 - m) = 1080 for m, and you get m is $10 000.
    judimary

    Answer by judimary at 11:26 PM on Mar. 6, 2011

  • Hahaha.....not just for fun. Could solve this, but it makes me want to do something else....like cry. LOL. Good luck.
    Kword

    Answer by Kword at 12:21 AM on Mar. 7, 2011

  • What? Did you mention something abt shopping? Unable to read your query...... Okay jokes apart my Maths is only okay; hoped it to be otherwise... I certainly hope one of us to help you.... :-)
    AnuMeha

    Answer by AnuMeha at 1:32 AM on Mar. 7, 2011

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