4(5x+1)(x+3)=0

[Anonymous]

Can you figure what (X) is?

Test your Algebra Skills.

[epoh]

I'm making a list of everyone who got the answer correct and I will be contacting you all when I start my math class.

[HouseKatof2]

 

[Anonymous - Original Poster]

lol

Quoting Aspirel:

No and you can't make me.

*runs from math*

[creoletexan]

Since it is factored, you can just set each term equal to zero:

(5x+1)=0

And

(x+3)=0

And solve for x for each one.

Quoting QJsmommy:

I guess ill try since my college class starts tomorrow.. I guess -3. 5x-3+1= -14 so 4(-14)(-3+3) .. 4x-14= -56.. -56(-3+3) -3+3=0, -56x0=0.. lol wow I have no idea if that's right but it looks good.

[SimplyErathy]

and this is why the hubs will be teaching algebra XD

[creoletexan]

If you start with expanding the expression first, you can use the quadratic formula.

Quoting angieo39:

5xsq+16x+3=0

5xsq=-16x-3

X



Im lost...its workable. X dosent =0 though. Are yall into negative integers

[GagaNTattooS]

Letters don't rqual numbers end of story. I hate math!!!

[Ashleeduhh]

0, obviously.

[midnight_storm]

X= -1/5, -3

[Ashleeduhh]

Wouldn't you add 14 to the other side making it 5x+12=0? But then it would be a fraction. So if it'd supposed to be a whole number...uhh lol I don't miss math.

Quoting creoletexan:

Since it is factored, you can just set each term equal to zero:



(5x+1)=0



And



(x+3)=0



And solve for x for each one.

Quoting QJsmommy:

I guess ill try since my college class starts tomorrow.. I guess -3. 5x-3+1= -14 so 4(-14)(-3+3) .. 4x-14= -56.. -56(-3+3) -3+3=0, -56x0=0.. lol wow I have no idea if that's right but it looks good.