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Help! I am stuck

Posted by on Aug. 26, 2008 at 12:18 PM
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I think I might have the answer, but I am not sure. Here is the question:

Solve the equation using the elimination method.

5x-4y=1

-10+8y=-3

Ok here is what I did first. I am not sure if I am heading in the right direction

8(5x-4y)=8(1)

4(-10+8y)=4(-3)

40x-32y=8

-40x+32y=-12

Now I am not sure what to do next. When I add, both x and y are droped. Is the answer no solution?

 

 

Posted by on Aug. 26, 2008 at 12:18 PM
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Karin78
by Group Admin on Aug. 27, 2008 at 10:37 AM

I'm not sure what the elimination method is.  I'll ask a couple of our math experts to take a look.

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KellyBTTW
by New Member on Aug. 27, 2008 at 12:57 PM

Thank you!!

esmom304
by Member on Aug. 27, 2008 at 6:23 PM

You are absolutely correct so far; and you're correct that the x and y will combine to be zero.  That means, you'll be left with 0=-4...is this a true statement?  Of course not.  So, therefore there is no solution to this system.  If you were to graph each equation, you would find that they never intersect (aka are parallel).

KellyBTTW
by New Member on Aug. 27, 2008 at 11:06 PM

Great thank you so much for your help.

Christy.Marie
by on Aug. 27, 2008 at 11:24 PM

They are parallel, you can check this by putting in slope intercept form and the slopes will be the same.  However, if you chose to do elimination just work with one equation at a time. For example I chose to multiply the first equation by -2 to eliminate the y variable first.

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