I can't for the life of me remember how to do this problem. I'm helping a friend with her math homework, but I'm so rusty. Can someone please help? Any info, even if it's just the equation, would be greatly appreciated! Thanks in advance! Here's the problem:
The length of a rectangle is three times its width. If the area of the rectangle is
, find its perimeter.
Thanks for the bump though!
Quoting cleanaturalady:
Eeek! I don't do math.

this is two parts. first is
L x W = area
so you have L x W = 75 sq in
since you know L is 3 times the width, you have:
lets call width X and so length will be 3X. Put these into your equation and get:
3X x X = 75 sq in
Can you solve from there?
then that gives you the L and W and you will use those to figure the perimeter using L + L + W + W = perimeter. Did that help? Sorry if it was late.
If you need more help write to TheMathMom here on cafemom - she is awesome!!!
Tonya
Great! Thank you! And, thanks for the referal!
Quoting sunmoonstars:
this is two parts. first is
L x W = area
so you have L x W = 75 sq in
since you know L is 3 times the width, you have:
lets call width X and so length will be 3X. Put these into your equation and get:
3X x X = 75 sq in
Can you solve from there?
then that gives you the L and W and you will use those to figure the perimeter using L + L + W + W = perimeter. Did that help? Sorry if it was late.
If you need more help write to TheMathMom here on cafemom - she is awesome!!!
Tonya

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- mommy2bunny
on Mar. 24, 2009 at 4:03 PM